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The formula of complex tris (ethylenedia...

The formula of complex tris (ethylenediamine) cobalt (III) sulphate is :

A

`[Ce(e n)_(2)SO_(4)]`

B

`[Co(e n)_(3)SO_(4)]`

C

`[Co (e n)_(3)]_(2) SO_(4)`

D

`[Co (e n)_(3)]_(2) (SO_(4))_(3)`

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The correct Answer is:
To determine the formula of the complex tris(ethylenediamine) cobalt(III) sulfate, we can break down the components step by step. ### Step 1: Identify the Cation and Anion - The cation in the complex is cobalt in the +3 oxidation state, denoted as Co(III). - The ligand is ethylenediamine (en), which is a neutral bidentate ligand. "Tris" indicates that there are three ethylenediamine ligands attached to the cobalt ion. - The anion is sulfate, which has a formula of SO₄²⁻ and carries a charge of -2. ### Step 2: Write the Cation Part - Since we have cobalt with three ethylenediamine ligands, we denote this as: - Cobalt: Co - Ethylenediamine: en - Since there are three ethylenediamine ligands, we write it as en₃. - Therefore, the cation part becomes: Co(en)₃. ### Step 3: Write the Anion Part - The anion is sulfate, which is represented as SO₄²⁻. ### Step 4: Combine Cation and Anion - The overall charge of the cation (Co(en)₃) is +3, and the charge of the sulfate (SO₄) is -2. - To balance the charges, we need to determine how many sulfate ions are required. Since the cation has a +3 charge and each sulfate has a -2 charge, we can find the least common multiple to balance the charges. - The least common multiple of +3 and -2 is 6. Therefore, we need 2 sulfate ions to balance the +3 charge from the cobalt complex. ### Step 5: Write the Final Formula - The final formula combines the cation and the anions: - Cation: Co(en)₃ - Anions: (SO₄)₂ - Therefore, the complete formula is: Co(en)₃(SO₄)₂. ### Step 6: Adjust for Tris - Since we have "tris" in the name, it indicates that there are three ethylenediamine ligands, which we have already accounted for. ### Final Answer The formula of the complex tris(ethylenediamine) cobalt(III) sulfate is: \[ \text{[Co(en)}_3\text{]}^{3+} \text{[SO}_4\text{]}^{2-} \] Thus, the final formula is: \[ \text{[Co(en)}_3\text{]} \text{(SO}_4\text{)}_2 \]
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