Complex ion `[CuCl_(2)(NH_(2)CoNH_(2)]` is named as

Options

A. dichloro bis (urea) copper (II)
B. bis (urea) dichloro copper (II)
C. dichloro bis (urea) copper (I)
D. bis (urea) dichloro copper (I)

Answer

To name the complex ion \([CuCl_2(NH_2CO(NH_2))_2]\), we will follow these steps:

### Step 1: Determine the oxidation state of copper (Cu)
- The complex has two chloride ions (Cl) which each have a charge of -1. Therefore, the total contribution from the chloride ions is \(-2\).
- Let \(x\) be the oxidation state of copper. Since the overall charge of the complex is neutral (0), we can set up the equation:
\[ x + (-2) = 0 \]
Solving for \(x\):
\[ x = +2 \]
- Thus, the oxidation state of copper in this complex is +2.

### Step 2: Identify the ligands
- The complex contains two types of ligands:
1. Chloride ions (Cl) - there are two of them, so we will use the prefix "dichloro".
2. Urea ligands (NH2CO(NH2)) - since there are two urea ligands, we will use the prefix "bis" to indicate two of them.

### Step 3: Combine the names of the ligands
- The name of the ligands will be combined as follows:
- The two chloride ligands will be named "dichloro".
- The two urea ligands will be named "bis urea".

### Step 4: Name the metal and its oxidation state
- The metal is copper, and since we have determined its oxidation state to be +2, we will denote this in Roman numerals as "copper(II)".

### Step 5: Write the full name of the complex
- Combining all parts together, we get:
\[ \text{dichlorobis(urea)copper(II)} \]

Thus, the complete name of the complex ion \([CuCl_2(NH_2CO(NH_2))_2]\) is **dichlorobis(urea)copper(II)**.

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