In Tollen.s reagent `[Ag(NH_(3))_(2)]^(+1)`. The oxidation number coordination number and effective atomic number of central metal ion are respectively
[Atomic number of Ag = 47]

Options

A. `+1, 2, 50`
B. `+1, 2, 51`
C. `+2, 1, 50`
D. ` +1, 1, 50`

Explanation

To solve the question regarding Tollen's reagent \([Ag(NH_3)_2]^{+1}\), we need to determine the oxidation number, coordination number, and effective atomic number of the central metal ion (Ag).

### Step-by-Step Solution:

1. **Identify the Central Metal Ion**:
The central metal ion in Tollen's reagent is silver (Ag).

2. **Determine the Oxidation Number**:
- The overall charge of the complex ion \([Ag(NH_3)_2]^{+1}\) is +1.
- The ammonia ligands (\(NH_3\)) are neutral, contributing 0 to the charge.
- Let the oxidation number of Ag be \(X\).
- The equation for the charge balance is:
\[ X + 2(0) = +1 \]
- Thus, \(X = +1\).
- **Oxidation Number of Ag**: +1.

3. **Determine the Coordination Number**:
- The coordination number is defined as the number of ligand atoms that are bonded to the central metal ion.
- In this case, there are 2 ammonia ligands (\(NH_3\)) attached to Ag.
- Therefore, the coordination number is:
\[ \text{Coordination Number} = 2. \]

4. **Calculate the Effective Atomic Number (EAN)**:
- The formula for EAN is:
\[ \text{EAN} = Z - X + Y \]
- Where:
- \(Z\) = Atomic number of the metal (Ag = 47),
- \(X\) = Oxidation number (which we found to be +1),
- \(Y\) = Number of electrons donated by ligands.
- Each \(NH_3\) ligand donates 2 electrons, and there are 2 ligands:
\[ Y = 2 \times 2 = 4. \]
- Now substituting the values into the EAN formula:
\[ \text{EAN} = 47 - 1 + 4 = 50. \]

### Final Results:
- **Oxidation Number**: +1
- **Coordination Number**: 2
- **Effective Atomic Number**: 50

Thus, the answer is:
- Oxidation number: +1
- Coordination number: 2
- Effective atomic number: 50