What is the probability of gamete AbC produced by a plant having genotype AaBbCc (If all the genes are situated on different chromosomes) ?

Options

A. `(1)/(2)`
B. `(1)/(4)`
C. `(1)/(6)`
D. `(1)/(8)`

Answer

To find the probability of the gamete AbC produced by a plant with the genotype AaBbCc, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype**: The genotype of the plant is AaBbCc. This means it has two alleles for each gene: A/a, B/b, and C/c.

2. **Determine Gamete Formation**: Since all genes are on different chromosomes, they assort independently during gamete formation. Each gene can contribute one of its two alleles to the gamete.

3. **Calculate Probability for Each Allele**:
- For the allele A (from Aa): There are two possibilities, A or a. The probability of getting A is 1/2.
- For the allele B (from Bb): There are two possibilities, B or b. The probability of getting b is also 1/2.
- For the allele C (from Cc): There are two possibilities, C or c. The probability of getting C is 1/2.

4. **Combine Probabilities**: To find the probability of forming the specific gamete AbC, we multiply the probabilities of each allele:
- Probability of A = 1/2
- Probability of b = 1/2
- Probability of C = 1/2

Therefore, the combined probability is:
\[ P(AbC) = P(A) \times P(b) \times P(C) = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} \]

5. **Conclusion**: The probability of producing the gamete AbC from the genotype AaBbCc is 1/8.

### Final Answer:
The probability of the gamete AbC produced by a plant with genotype AaBbCc is **1/8**.

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