A white fruit colour of summer squash plant of genotype WwYy is crossed with plant having genotype wwyy then :-

Options

A. 25% offspring will have yellow fruits
B. All progeny plant having white fruits
C. 75% plant have white fruits
D. 6.25% plant have green fruits

Answer

To solve the problem, we need to analyze the genetic cross between the two summer squash plants with the given genotypes. Let's break it down step by step.

### Step 1: Identify the Genotypes
We have two plants:
1. Plant 1 (white fruit): Genotype WwYy
2. Plant 2 (green fruit): Genotype wwyy

### Step 2: Determine the Gametes
Next, we need to determine the possible gametes that each plant can produce.
- Plant 1 (WwYy) can produce the following gametes: WY, Wy, wY, wy.
- Plant 2 (wwyy) can only produce one type of gamete: wy.

### Step 3: Set Up the Punnett Square
Now, we can set up a Punnett square to visualize the potential offspring from the cross.

| | wy | wy |
|-------|------|------|
| **WY**| WwYy | WwYy |
| **Wy**| Wwyy | Wwyy |
| **wY**| wwYy | wwYy |
| **wy**| wwyy | wwyy |

### Step 4: Analyze the Offspring
Now we can analyze the phenotypes of the offspring based on the genotypes:
- WwYy (white fruit)
- WwYy (white fruit)
- Wwyy (white fruit)
- Wwyy (white fruit)
- wwYy (yellow fruit)
- wwYy (yellow fruit)
- wwyy (green fruit)
- wwyy (green fruit)

### Step 5: Count the Phenotypes
Now, let's count the phenotypes:
- White fruits: 4 (WwYy and Wwyy)
- Yellow fruits: 2 (wwYy)
- Green fruits: 2 (wwyy)

### Step 6: Calculate the Percentages
Now we can calculate the percentage of each phenotype:
- White fruits: 4 out of 8 = 50%
- Yellow fruits: 2 out of 8 = 25%
- Green fruits: 2 out of 8 = 25%

### Conclusion
From the analysis, we find that:
- 50% of the offspring will have white fruits.
- 25% of the offspring will have yellow fruits.
- 25% of the offspring will have green fruits.

### Final Answer
The correct statement is: **25% of the offspring will have yellow fruits.**

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