In Pea plant, when homozygous round seeded plant is crossed with homozygous wrinkled seeded plant, then the offsprings will be :-

Options

A. 100 % with large starch grains
B. 75 % with medium sized starch grains
C. 25 % with small sized starch grains
D. 0 % with small sized starch grains

Answer

To solve the question regarding the offspring of a cross between a homozygous round-seeded pea plant and a homozygous wrinkled-seeded pea plant, we can follow these steps:

### Step 1: Identify the Genotypes
- The homozygous round-seeded plant has the genotype **RR** (where R represents the dominant allele for round seeds).
- The homozygous wrinkled-seeded plant has the genotype **rr** (where r represents the recessive allele for wrinkled seeds).

### Step 2: Determine the Gametes
- The round-seeded plant (RR) can only produce gametes with the allele **R**.
- The wrinkled-seeded plant (rr) can only produce gametes with the allele **r**.

### Step 3: Perform the Cross
- When we cross the two plants, we combine the gametes:
- From the round-seeded plant: **R**
- From the wrinkled-seeded plant: **r**

The resulting genotype of the offspring will be **Rr**.

### Step 4: Analyze the Offspring Phenotype
- The genotype **Rr** indicates that the offspring will have round seeds because the round seed trait (R) is dominant over the wrinkled seed trait (r).
- Therefore, all offspring will exhibit the round seed phenotype.

### Step 5: Conclusion
- The offspring of the cross between a homozygous round-seeded plant and a homozygous wrinkled-seeded plant will be **100% round-seeded**.

### Summary of the Answer
The offspring will be 100% round-seeded (Rr).

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