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Unpolarized light of intensity 32Wm^(-2)...

Unpolarized light of intensity `32Wm^(-2)` passes through three polarizers such that transmission axes of the first and second polarizer make an angle `30^@` with each other and the transmission axis of the last polarizer is crossed with that of the first . The intensity of the final emerging light will be

A

32 watt `m^(-2)`

B

3 watt `m^(-2)`

C

8 watt `m^(-2)`

D

4 watt `m^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(0)` is intensity of unpolarized incident light
`I=(I_(0))/(2)cos^(2)30^(@)" "cos^(2)60^(@)=3` watt `m^(-2)`
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