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A 0.010 M solution of a monoprotic acid(...

A 0.010 M solution of a monoprotic acid(`d = 1.01 g //cm^(3)`) is 5% dissociated What is the freezing point of the solution? The mol. Mass of the acid is 300 and `K_(f)(H_(2)O)` = `1.86^(@)C` / m:

A

`-0.189^(@)C`

B

`-0.194^(@)C`

C

`-0.199^(@)C`

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
Mass of 1 litre of solution =1010 gram
mass of solvent =1010 `-300xx0.1=980` gram
`m=(0.1)/(0.98)=0.102`
`DeltaT_(f)=iK_(f)m=(1+alpha)K_(f)m`
`impliesDeltaT_(f)=0.199^(@)C`
`impliesT_(f)=0-0.199^(@)C=-0.199^(@)C`
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