Home
Class 12
CHEMISTRY
In the spinel structur, oxides ions are ...

In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by `A^(2+)` cation and 1/2 of octahedral voids are occupied by `B^(+)` cations. The general formula of the compound having spinel structure is:

A

`A_(2)B_(2)O_(4)`

B

`AB_(2)O_(4)`

C

`A_(2)B_(4)O_(2)`

D

`A_(4)B_(2)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

Effective number of `O^(2-)` in a unit cell `=8xx(1)/(8)+6xx(1)/(2)=4`
Effective number of `A^(2+)` in a unit cell `=8xx(1)/(8)=1`
Effective number of `B^(3+)` in a unit cell `=4xx(1)/(2)=2`
`therefore` General formula `=AB_(2)O_(4)`
Promotional Banner

Similar Questions

Explore conceptually related problems

In HCP or CCP constituent particles occupy 74% of the available space. The remaining space (26%) in between the spheres remains unoccupied and is called interstitial voids or holes. Considering the close packing arrangement, each sphere in the second layer rests on the hollow space of the first layer, touching each other. The void created is called tetrahedral void. If R is the radius of the spheres in the close packed arrangement then, R (radius of tetrahedral void) = 0.225 R In a close packing arrangement, the interstitial void formed by the combination of two triangular voids of the first and second layer is called octahedral coid. Thus, double triangular void is surrounded by six spheres. The centre of these spheres on joining, forms octahedron. If R is the radius of the sphere. in a close packed arrangement then, R (radius of octahedral void = 0.414 R). In the spinel structure, oxide ions are cubic close packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cations and 1/2 of octahedral voids are occupied by B^(3+) cations. The general formula of the compound having spinel structure is

In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by Zn^(2+) ions and 50% of octahedral holes are occupied by Fe^(3+) ions. The formula of the compound is -

In solid oxide are arranged in ccp .One - sixth of tetrabedral voids are occupied by cation A which one third of octahedral voids are occupied by cation B .What is the formula of compound ?

In a close packed structure of mixed oxides , the lattice is composed of oxide ions , one eighth of tetrahedral voids are occupied by divalent cations while one half of octahedral voids are occupied by trivalent cations . What is the formula of the oxide ?

In a cubic close packed structure of mixed oxides, the lattice is made up of oxide ions, one eight of tetrahedral voids are occupied by divalent (X^(2+)) ions, while one - half of the octahedral voids are occupied by trivalent ions (Y^(3+)) , then the formula of the oxide is

AgI crystallises in a cubic close-packed ZnS structure. What fraction of tetrahedral sites is occupied by Ag^(+) ions ?

In a cubic packed structure of mixed oxides the lattice is made up of oxide ions. One fifth of tetrahedral voids are occupied by divalent (X^(2+)) ions, while one - half of the octahedral voids are occupied by trivalent ions (Y^(3+)) then the formula of the oxide is:

Structure of a mixed oxide is cubic close packed the cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal.A and the octahedral voids are occupied by a monvalent metal B . The formula of the oxide is :

In a compound, oxide ions are arranged in ccp . One-sixth of the tetrahedral voids are occupied by cations. (A) and one-third of OV_(s) are occupieed by cations (B) . (a) What is the formula of the compound of the compound? (b) What are the charges on A and B ?

In a compound,oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahdral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is