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The cell Pt|H(2)(g,01 bar) |H^(+)(aq),pH...

The cell `Pt|H_(2)(g,01` bar) `|H^(+)(aq),pH=x||Cl^(-)(1M)|Hg_(2)Cl_(2)|Hg|Pt` has emf of 0.5755 V at `25^(@)C` the SOP of calomel electrode is `-0.28V` then pH of the solution will be
(a)11
(b)4.5
(c)5
(d)None of these

A

11

B

4.5

C

5.5

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
For normal calomel electrode `E_(RP)=E_(RP)^(@)`
`E_(cell)=(0.28-0)-(0.059)/(2)log(([H^(+)]^(2))/(P_(H_(2))))impliespH=5.5`
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