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Both the strings, shown in figure, are m...

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is

A

1

B

2

C

`sqrt(2)`

D

`1//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=sqrt((T)/(mu)): " "V_(AB)=sqrt((T)/(mu))" ",V_(CD)=sqrt((2T)/(mu))`
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