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1.2 L of 0.4 M HCl solution can be compl...

1.2 L of 0.4 M HCl solution can be completely neutralized by

A

600 mL of 1.2 M NaOH solution

B

800 mL of 0.2 M NaOH solution

C

19.2 g of solid NaOH

D

4.8 mole of NaOH

Text Solution

Verified by Experts

The correct Answer is:
C
Moles of HCl`=(1200xx0.4)/(1000)=0.48`
Moles of `NaOH=(19.2)/(40)=0.48`
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