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CH(3)CH(2)underset(CH(3))underset(|)(C)=...

`CH_(3)CH_(2)underset(CH_(3))underset(|)(C)=CHCH_(3)overset("Reagent")toCH_(3)CH_(2)underset(CH_(3))underset(|)(CH)overset(OH)overset(|)(CH)CH_(3)`
Which reagent forms the above organic product as the single product in the above reaction?

A

`H_(2)O //H^(+)`

B

`(Hg(OCOCH_(3))_(2),H_(2)O)/(NaBH_(4))`

C

`(B_(2)H_(6),THF)/(NaOH,H_(2)O_(2))`

D

`KMnO_(4)//OH^(-)//"Cold"`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which reagent forms the given organic product as a single product, we need to analyze the structure of the reactant and the product. The reactant is a substituted alkene, and the product is a secondary alcohol. 1. **Identify the structure of the reactant and product**: - The reactant is a substituted alkene with a double bond between the second and third carbon atoms, and a methyl group attached to the third carbon. - The product is a secondary alcohol with the hydroxyl group (OH) on the second carbon. 2. **Consider the reagents**: - **Option A: Simple Hydration**: This involves adding water (H2O) across the double bond. According to Markovnikov's rule, the hydrogen will add to the less substituted carbon, which would lead to a tertiary alcohol, not a secondary alcohol. - **Option B: Oxymercuration-Demercuration**: This method involves the addition of mercuric acetate followed by reduction. The reaction proceeds through a cyclic mercurinium ion, leading to Markovnikov addition. This would yield a secondary alcohol, as the nucleophile (water) would attack the more substituted carbon. - **Option C: Hydroboration-Oxidation**: This method typically results in anti-Markovnikov addition and is not suitable for this structure since it is a non-terminal alkene. Therefore, it would not yield the desired product. - **Option D: Baeyer's Reagent (KMnO4)**: This reagent oxidizes alkenes to diols, resulting in the formation of a glycol, which is not the desired product. 3. **Conclusion**: - After analyzing all options, **Option B (Oxymercuration-Demercuration)** is the only reagent that will yield the secondary alcohol as a single product. ### Final Answer: The reagent that forms the above organic product as the single product in the reaction is **Option B: Oxymercuration-Demercuration**.

To determine which reagent forms the given organic product as a single product, we need to analyze the structure of the reactant and the product. The reactant is a substituted alkene, and the product is a secondary alcohol. 1. **Identify the structure of the reactant and product**: - The reactant is a substituted alkene with a double bond between the second and third carbon atoms, and a methyl group attached to the third carbon. - The product is a secondary alcohol with the hydroxyl group (OH) on the second carbon. 2. **Consider the reagents**: - **Option A: Simple Hydration**: This involves adding water (H2O) across the double bond. According to Markovnikov's rule, the hydrogen will add to the less substituted carbon, which would lead to a tertiary alcohol, not a secondary alcohol. ...
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