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In the shown diagram two point masses m ...


In the shown diagram two point masses m are joined by a massless rod of length 5.5m. The lower end of the mass sytem is dragged with constant velocity `V_(0)` rightwards the magnitude of velocity of centre of mass when `theta=37^(0)`, will be

A

`(5v_(0))/(6)`

B

`2v_(0)`

C

`v_(0)sqrt(2)`

D

`(6v_(0))/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
`x^(2)+y^(2)=l^(2)`
`(dy)/(dt)=-(x)/(y)((dx)/(dt))`
if `theta=37^(@)`
`(dy)/(dt)=-(x)/(y)(dx)/(dt)=-(4)/(3)v_(@)`
`vecv_(cm)=(mv_(@)hati-m(4v_(@))/(3)haty)/(2m)`
`|vecV_(cm)|=(5v_(@))/(6)`
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