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Given (i) Cu^(2+)+2e^(-) to Cu, E^(@)...

Given
`(i) Cu^(2+)+2e^(-) to Cu, E^(@)=0.337V`
`(ii) Cu^(2+)+e^(-) to Cu^(+), E^(@)=0.153 V`
Electrode potential, `E^(@)` for the reaction, `Cu^(+)+e^(-) to Cu`, will be

A

`2.9xx10^(-8)`

B

`3.72xx10^(-7)`

C

`2.9xx10^(-5)`

D

`3.72xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`CutoCu^(2+)+2e^(-)" "DeltaG_(1)^(0)`
`2Cu^(2+)+2e^(-)to2Cu^(+)" "DeltaG_(2)^(0)`
`DeltaG_(f)^(0)=DeltaG_(1)+DeltaG_(2)`
`DeltaG_(f)^(0)=-2.303RTlogK`
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