`CH_(3)CH_(2)CH_(2)Cl+CH_(3)underset(Cl)underset(|)(C)HCH_(3)underset("dry ether")overset(Na)to` Products.
Which of te following is not a product of above reaction?

Options

A.
B.
C.
D.

Explanation

To solve the question regarding the products formed from the reaction of propyl chloride (CH₃CH₂CH₂Cl) and isopropyl chloride (CH₃ClC(CH₃)H) in the presence of sodium in dry ether, we will follow these steps:

### Step 1: Identify the Reaction Type
This reaction is known as the Wurtz reaction, which involves the coupling of alkyl halides in the presence of sodium metal to form higher alkanes.

**Hint:** Remember that Wurtz reaction typically leads to the formation of symmetrical alkanes.

### Step 2: Write the Reactants
The reactants are:
1. Propyl chloride: CH₃CH₂CH₂Cl
2. Isopropyl chloride: CH₃C(Cl)(CH₃)

### Step 3: Determine the Free Radicals
In the presence of sodium, the halogen atoms (Cl) are removed, leading to the formation of free radicals:
1. Propyl free radical: CH₃CH₂CH₂• (from propyl chloride)
2. Isopropyl free radical: CH₃C•(CH₃)

### Step 4: Possible Coupling Reactions
Now, we can consider the possible combinations of these free radicals:
1. **Propyl + Propyl**:
- CH₃CH₂CH₂• + CH₃CH₂CH₂• → CH₃(CH₂)₃CH₃ (n-hexane)

2. **Isopropyl + Isopropyl**:
- CH₃C•(CH₃) + CH₃C•(CH₃) → (CH₃)₂C(CH₃)₂ (2,3-dimethylbutane)

3. **Propyl + Isopropyl**:
- CH₃CH₂CH₂• + CH₃C•(CH₃) → CH₃CH₂C(CH₃)(CH₂) (2-methylpentane)

### Step 5: List the Products
From the above combinations, the products formed are:
1. n-Hexane (from propyl + propyl)
2. 2,3-Dimethylbutane (from isopropyl + isopropyl)
3. 2-Methylpentane (from propyl + isopropyl)

### Step 6: Identify the Incorrect Product
The question asks which of the following is **not** a product of the reaction. Based on the analysis, we have:
- n-Hexane
- 2,3-Dimethylbutane
- 2-Methylpentane

If there is an option that does not match any of these products, that will be the answer.

### Conclusion
After analyzing the products formed, we conclude that the option that is not a product of the reaction is **Option D**.

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