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Molar heat capacity of an ideal gas at c...

Molar heat capacity of an ideal gas at constant volume is given by `C_(V)=2xx10^(-2)J` (in Joule). If 3.5 mole of hits ideal gas are heated at constant volume from 300K to 400K the change in internal energy will be

A

7

B

4

C

8

D

6

Text Solution

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The correct Answer is:
To solve the problem, we need to calculate the change in internal energy (\( \Delta U \)) of the ideal gas using the formula: \[ \Delta U = n \cdot C_V \cdot \Delta T \] Where: - \( n \) = number of moles of the gas - \( C_V \) = molar heat capacity at constant volume - \( \Delta T \) = change in temperature ### Step 1: Identify the given values - Molar heat capacity \( C_V = 2 \times 10^{-2} \, \text{J/mol K} \) - Number of moles \( n = 3.5 \, \text{moles} \) - Initial temperature \( T_1 = 300 \, \text{K} \) - Final temperature \( T_2 = 400 \, \text{K} \) ### Step 2: Calculate the change in temperature (\( \Delta T \)) \[ \Delta T = T_2 - T_1 = 400 \, \text{K} - 300 \, \text{K} = 100 \, \text{K} \] ### Step 3: Substitute the values into the formula for \( \Delta U \) Now we can substitute the values into the formula: \[ \Delta U = n \cdot C_V \cdot \Delta T \] \[ \Delta U = 3.5 \, \text{moles} \cdot (2 \times 10^{-2} \, \text{J/mol K}) \cdot (100 \, \text{K}) \] ### Step 4: Perform the multiplication Calculating the multiplication step by step: 1. First, calculate \( C_V \cdot \Delta T \): \[ C_V \cdot \Delta T = (2 \times 10^{-2} \, \text{J/mol K}) \cdot (100 \, \text{K}) = 2 \, \text{J/mol} \] 2. Now multiply by the number of moles: \[ \Delta U = 3.5 \, \text{moles} \cdot 2 \, \text{J/mol} = 7 \, \text{J} \] ### Step 5: Final answer Thus, the change in internal energy is: \[ \Delta U = 7 \, \text{J} \]

To solve the problem, we need to calculate the change in internal energy (\( \Delta U \)) of the ideal gas using the formula: \[ \Delta U = n \cdot C_V \cdot \Delta T \] Where: - \( n \) = number of moles of the gas ...
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