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A small pulse is generated on a ring rot...


A small pulse is generated on a ring rotating with constant angular velocity `omega` as shown in the figure. Then the speed of pulse with respect to ground.

A

`omegaR`

B

`omegaR//2`

C

`2omegaR`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
`2Tsintheta=dmomegat^(2)R`
`approx2Ttheta=mudlomega^(2)R`
`approx2Ttheta=muR^(2)thetaomega^(2)R`
`implies(T)/(mu)omega^(2)R^(2)`
or `v_(wave)=omegaR`
Note `v_(wave)` obtained is always with respect to medium.
`thereforev_("wave/ground")=omegaR-omegaR`
`=0`
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