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A transmitting antenna at te top of a to...

A transmitting antenna at te top of a tower has a height 64 m and the height of the receiving antenna is 100 m. The maximum distance between them for satisfactory communication in LOS mode will be {approximately}

A

45.5 km

B

91 km

C

136.5 km

D

182.0 km

Text Solution

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The correct Answer is:
To solve the problem of finding the maximum distance for satisfactory communication in Line of Sight (LOS) mode between a transmitting antenna and a receiving antenna, we can use the formula for the distance to the radio horizon. The formula is given by: \[ d_m = \sqrt{2 \cdot R \cdot h_T} + \sqrt{2 \cdot R \cdot h_R} \] Where: - \( d_m \) = maximum distance for satisfactory communication - \( R \) = radius of the Earth (approximately \( 6.4 \times 10^6 \) meters) - \( h_T \) = height of the transmitting antenna (64 meters) - \( h_R \) = height of the receiving antenna (100 meters) ### Step-by-Step Solution: 1. **Identify the given values**: - Height of transmitting antenna, \( h_T = 64 \, \text{m} \) - Height of receiving antenna, \( h_R = 100 \, \text{m} \) - Radius of the Earth, \( R = 6.4 \times 10^6 \, \text{m} \) 2. **Calculate the first term**: \[ \sqrt{2 \cdot R \cdot h_T} = \sqrt{2 \cdot (6.4 \times 10^6) \cdot 64} \] - Calculate \( 2 \cdot 6.4 \times 10^6 \cdot 64 \): \[ 2 \cdot 6.4 \times 10^6 \cdot 64 = 819.2 \times 10^6 \] - Now take the square root: \[ \sqrt{819.2 \times 10^6} \approx 28.62 \, \text{km} \] 3. **Calculate the second term**: \[ \sqrt{2 \cdot R \cdot h_R} = \sqrt{2 \cdot (6.4 \times 10^6) \cdot 100} \] - Calculate \( 2 \cdot 6.4 \times 10^6 \cdot 100 \): \[ 2 \cdot 6.4 \times 10^6 \cdot 100 = 1280 \times 10^6 \] - Now take the square root: \[ \sqrt{1280 \times 10^6} \approx 35.77 \, \text{km} \] 4. **Add both terms to find the maximum distance**: \[ d_m = 28.62 \, \text{km} + 35.77 \, \text{km} = 64.39 \, \text{km} \] 5. **Round the answer**: The maximum distance for satisfactory communication in LOS mode is approximately: \[ d_m \approx 64.40 \, \text{km} \] ### Final Answer: The maximum distance between the transmitting and receiving antennas for satisfactory communication in LOS mode is approximately **64.40 km**.

To solve the problem of finding the maximum distance for satisfactory communication in Line of Sight (LOS) mode between a transmitting antenna and a receiving antenna, we can use the formula for the distance to the radio horizon. The formula is given by: \[ d_m = \sqrt{2 \cdot R \cdot h_T} + \sqrt{2 \cdot R \cdot h_R} \] Where: - \( d_m \) = maximum distance for satisfactory communication - \( R \) = radius of the Earth (approximately \( 6.4 \times 10^6 \) meters) - \( h_T \) = height of the transmitting antenna (64 meters) ...
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Knowledge Check

  • A transmitting antenna at the top of the tower has a height 18 m and the height of the receiving antenna is 32m. The maximum distance between them for satisfactory communciation in line of sight mode is (Radius of earth = 6.4xx10^(6)m )

    A
    15.15km
    B
    21.25km
    C
    30.45km
    D
    35.42km.
  • A transmitting antenna at the top of the tower has a height 18 m and the height of the receiving antenna is 32m. The maximum distance between them for satisfactory communciation in line of sight mode is (Radius of earth = 6.4xx10^(6)m )

    A
    15.15km
    B
    21.25km
    C
    30.45km
    D
    35.42km.
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