Iodate ions can be reduced to iodine by iodide ions as per the given redox reaction in acidic medium.
`lO_(3)^(-)(aq)+l^(-)(aq)tol_(2)(S)`.
How many moles of iodine are produced for every mole of iodate ions consumed in the reaction?

Options

A. 1
B. 2.5
C. 3
D. 5

Explanation

To determine how many moles of iodine are produced for every mole of iodate ions consumed in the given redox reaction, we will balance the reaction step by step.

### Step 1: Write the unbalanced equation
The unbalanced reaction is:
\[ \text{IO}_3^{-} (aq) + \text{I}^{-} (aq) \rightarrow \text{I}_2 (s) \]

### Step 2: Assign oxidation states
- In iodate (\( \text{IO}_3^{-} \)), iodine has an oxidation state of +5.
- In iodide (\( \text{I}^{-} \)), iodine has an oxidation state of -1.
- In solid iodine (\( \text{I}_2 \)), iodine has an oxidation state of 0.

### Step 3: Determine the changes in oxidation states
- The iodate ion (\( \text{IO}_3^{-} \)) is reduced from +5 to 0 (gaining 5 electrons).
- The iodide ion (\( \text{I}^{-} \)) is oxidized from -1 to 0 (losing 1 electron).

### Step 4: Balance the half-reactions
To balance the electrons transferred:
- For every 2 moles of \( \text{IO}_3^{-} \) reduced, 10 moles of \( \text{I}^{-} \) are required to produce 6 moles of \( \text{I}_2 \).

### Step 5: Write the balanced equation
The balanced equation can be written as:
\[ 2 \text{IO}_3^{-} + 10 \text{I}^{-} + 12 \text{H}^{+} \rightarrow 6 \text{I}_2 + 6 \text{H}_2O \]

### Step 6: Determine the stoichiometry
From the balanced equation, we see that:
- 2 moles of \( \text{IO}_3^{-} \) produce 6 moles of \( \text{I}_2 \).

### Step 7: Calculate moles of iodine produced per mole of iodate
To find out how many moles of iodine are produced for every mole of iodate:
- For 2 moles of \( \text{IO}_3^{-} \), 6 moles of \( \text{I}_2 \) are produced.
- Therefore, for 1 mole of \( \text{IO}_3^{-} \):
\[ \text{Moles of } I_2 = \frac{6 \text{ moles } I_2}{2 \text{ moles } IO_3^{-}} = 3 \text{ moles } I_2 \]

### Final Answer
Thus, for every mole of iodate ions consumed, **3 moles of iodine are produced**.

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