In the following statement, which combination of true (T) and false (F) options in correct?
(A). Ionic mobility is highest of `I^(-)` in water as compared to other halides.
(B). `IF_(5)` is square pyramidal and `IF_(7)` is pentangonal bipyramidal in shape
(C). Reactivity order is `F_(2)ltCl_(2)ltBr_(2)ltI_(2)`
(D). Oxidising power order is `F_(2)ltCl_(2)ltBr_(2)ltI_(2)`

Options

A. TFTF
B. TTFT
C. TTTT
D. TTFF

Explanation

To determine the truthfulness of the statements provided in the question, we will analyze each statement step by step.

### Step 1: Analyze Statement A
**Statement A:** Ionic mobility is highest for `I^(-)` in water as compared to other halides.

- **Explanation:** Ionic mobility refers to the ability of an ion to move through a solvent. The ionic mobility is influenced by the size of the ion and its hydration.
- Iodide ion (`I^(-)`) is larger than bromide (`Br^(-)`), chloride (`Cl^(-)`), and fluoride (`F^(-)`).
- The smaller the ion, the greater the hydration energy, which means the ion is surrounded by more water molecules and experiences more resistance to movement.
- Therefore, since `I^(-)` is the largest ion among the halides, it has the least hydration and thus the highest ionic mobility.

**Conclusion:** Statement A is **True (T)**.

### Step 2: Analyze Statement B
**Statement B:** `IF_(5)` is square pyramidal and `IF_(7)` is pentagonal bipyramidal in shape.

- **Explanation for `IF_(5)`:**
- The central iodine atom has 5 fluorine atoms bonded to it and one lone pair of electrons.
- This results in a total of 6 electron pairs (5 bond pairs + 1 lone pair).
- The geometry is octahedral, but the shape is square pyramidal due to the presence of the lone pair.

- **Explanation for `IF_(7)`:**
- The central iodine atom has 7 fluorine atoms bonded to it and no lone pairs.
- This results in a total of 7 bond pairs.
- The shape of `IF_(7)` is indeed pentagonal bipyramidal.

**Conclusion:** Statement B is **True (T)**.

### Step 3: Analyze Statement C
**Statement C:** Reactivity order is `F_(2) < Cl_(2) < Br_(2) < I_(2)`.

- **Explanation:** Reactivity of halogens generally increases as you move up the group in the periodic table.
- Fluorine (`F2`) is the most reactive halogen due to its high electronegativity and ability to attract electrons.
- The correct order of reactivity should be `F2 > Cl2 > Br2 > I2`.

**Conclusion:** Statement C is **False (F)**.

### Step 4: Analyze Statement D
**Statement D:** Oxidising power order is `F_(2) < Cl_(2) < Br_(2) < I_(2)`.

- **Explanation:** The oxidizing power of halogens decreases down the group.
- Fluorine is the strongest oxidizing agent, followed by chlorine, bromine, and iodine.
- Therefore, the correct order of oxidizing power should be `F2 > Cl2 > Br2 > I2`.

**Conclusion:** Statement D is **False (F)**.

### Final Summary
- **A:** True (T)
- **B:** True (T)
- **C:** False (F)
- **D:** False (F)

### Final Answer
The correct combination of true (T) and false (F) options is: **TTFF**.

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