Which of the following compounds loses `CO_(2)` upon heatiring to `100^(@)C`

Options

A.
B.
C.
D.

Explanation

To determine which compound loses CO₂ upon heating to 100°C, we need to analyze the options provided. The key concept here is that certain compounds, particularly beta-keto acids, can lose carbon dioxide when heated due to the stability of the carbanion formed during the process.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to analyze the structures of the compounds given in the options (A, B, C, D) to see which one is a beta-keto acid.

2. **Understand Beta-Keto Acids**:
Beta-keto acids have a structure where a ketone group (C=O) is adjacent to a carboxylic acid group (–COOH). This structural arrangement allows for the formation of a carbanion when CO₂ is lost upon heating.

3. **Analyze Option A**:
- Option A is a cyclic compound with a carboxylic group and a ketone group.
- Upon heating, it can lose CO₂, forming a stable carbanion due to resonance stabilization from the adjacent carbonyl group.

4. **Analyze Option B**:
- Option B lacks any electron-withdrawing groups.
- Without stabilization, it is less likely to lose CO₂ upon heating.

5. **Analyze Option C**:
- Option C has an –OH group, which is an electron-donating group.
- This destabilizes the carbanion that would form if CO₂ were to be lost.

6. **Analyze Option D**:
- Option D has two carboxylic acid groups.
- The presence of two acidic groups makes it unlikely for CO₂ to be lost, as both would destabilize the formation of a carbanion.

7. **Conclusion**:
- Based on the analysis, only Option A, which is a beta-keto acid, can readily lose CO₂ upon heating to 100°C due to the resonance stabilization of the carbanion formed.

### Final Answer:
The compound that loses CO₂ upon heating to 100°C is **Option A** (the beta-keto acid).

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