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A man moving on track ABC, getting rain ...

A man moving on track ABC, getting rain drops vertical for the path AB, and along same line of its motion for path BC then actual speed of rain drop is

A

`10sqrt3ms^(-1)`

B

`(10)/(sqrt3)ms^(-1)`

C

`5sqrt3ms^(-1)`

D

Can't find

Text Solution

Verified by Experts

The correct Answer is:
B
`bar(V)_(R ) = V_(x)i +V_(y)i`

For path AB `V_(x) = 5 ms^(-1)`
For path BC velocity of rain `_|_r` to BC should be zero hence
`V_(x)sin30^(@) = V_(y)cos30^(@) V_(y) = (5)/(sqrt3)ms^(-1)`
`V_(R ) = sqrt(V_(x)^(2)+V_(y)^(2))= (10)/(sqrt3)ms^(-1)`
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