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One mole of a monoatomic gas undergoes a...

One mole of a monoatomic gas undergoes a linear process `A rarr B` in `P - v` diagram. The volume of the gas when the process turns from an endothermic to an exothermic one is

A

`(5)/(8)v_(0)`

B

`(v_(0))/(2)`

C

`(8v_(0))/(15)`

D

`(3v_(0))/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
the point where adiabatic curve touch the line AB the nature of process will change from endo thermic to exothermic.

`-(P_(0))/(v_(0))=-gamma(P)/(V)`
`-m=-(gamma(-mv+P_(0)))/(V) m =+(P_(0))/(V_(0))`
`mv(1+gamma)=gammaP_(0) " " V=(gammaP_(0))/(m(1+gamma))=(5)/(8)V_(0)`
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