Home
Class 12
PHYSICS
A non uniform cylinder of mass m, length...

A non uniform cylinder of mass `m`, length `l` and radius `r` having its C.O.M at a distance `(l)/(4)` from centre and lying on axis of cylinder . The cylinder is kept in a liquid of unifrom density `rho`. The moment of inertia of the rod about C.O.M is I. The angular acceleration of point A relative to point B just after the rod is released from position shown in figure is .

A

`(pirhogl^(2)r^(2))/(2I)`

B

`(3pirhogl^(2)r^(2))/(4I)`

C

`(pirhogl^(2)r^(2))/(I)`

D

`(pirhogl^(2)r^(2))/(4I)`

Text Solution

Verified by Experts

The correct Answer is:
D
`F_("Buoyancy")=piR^(2)lrhog`

T orque `=(pir^(2)l^(2)rhog)/(4)`
`alpha=(pi^(2)l^(2)rhogr^(2))/(4I)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A non-uniform cylinder of mass m , length l and radius r is having its centre of mass at a distance l.4 from the centre and lying on the axis of the cylinder. The cylinder is kept in a liquid of uniform density rho . The moment of inertia of the rod about the centre of mass is l . The angular acceleration of point A relative to point B just after the rod is released from the position as shown in the figure is

A non-uniform rod of mass m , length l and radius r is having its centre of mass at a distance l//4 from the centre and lying on the axis of the cylinder. The cylinder is kept in a liquid of uniform density rho . The moment of inertia of the rod about the centre of mass is I . The angular acceleration of point A relative to point B just after the rod is released from the position as shown in the figure is

A uniform rod AB of length l and mass m is free to rotate about an Axis passing through A and perpendicular to length of the rod. The rod is released from rest as shown in figure. Given that the moment of inertia of the rod about A is (ml^(2))/3 The initial angular acceleration of the rod will be

Find the moment of inertia of the rod AB about an axis yy as shown in figure. Mass of the rod is m and length is l.

The mass of the cylinder is 25 kg and radius of cylinder is 5 m. Find the moment of inertia of a solid cylinder about a tangent to the cylinder.

A uniform rod of mass 20 Kg and length 1.6 m is piovted at its end and swings freely in the vertical plane. Angular acceleration of the rod just after the rod is relased from rest in the horizontal position is

The moment of inertia of cylinder of radius a, mass M and height h about an axis parallel to the axis of the cylinder and distance b from its centre is :

A particle mass m is attched to a thin uniform rod of length a at a distance of (a)/(4) from the mid-point C as shown in the figure. The mass of the rod is 4m The moment of inertia of the combined system about an axis passing through O and perpendicular to the rod is

A uniform thin rod of length l and mass m is hinged at a distance l//4 from one of the end and released from horizontal position as shown in Fig. The angular velocity of the rod as it passes the vertical position is

A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is (ml^ 2 ) / ( 3 ) , the initial angular acceleration of the rod will be