In the exteraction of copper from its sulphide ore, the metal is fanally obtained by the reduction of caprous oxide with

Options

A. `CO`
B. `FeS`
C. `SO_(2)`
D. `Cu_(2)S`

Explanation

To solve the question regarding the extraction of copper from its sulphide ore, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Sulphide Ore of Copper**:
- The primary sulphide ore of copper is **Cu2S**, known as copper(I) sulfide or chalcopyrite.

2. **Roasting Process**:
- The first step in the extraction of copper from its sulphide ore is **roasting**. This involves heating the finely powdered ore in the presence of oxygen.
- The chemical reaction during roasting converts copper(I) sulfide (Cu2S) into copper(I) oxide (Cu2O) and sulfur dioxide (SO2):
\[ 2 \text{Cu}_2\text{S} + 3 \text{O}_2 \rightarrow 4 \text{Cu}_2\text{O} + 2 \text{SO}_2 \]

3. **Reduction of Cuprous Oxide**:
- After obtaining cuprous oxide (Cu2O), the next step is to reduce it to metallic copper (Cu).
- The reducing agent used for this reduction is **cuprous sulfide (Cu2S)**, which reacts with cuprous oxide:
\[ \text{Cu}_2\text{O} + \text{Cu}_2\text{S} \rightarrow 4 \text{Cu} + \text{SO}_2 \]
- In this reaction, cuprous sulfide acts as the reducing agent, donating electrons to reduce cuprous oxide to copper.

4. **Final Product**:
- The final product of this reduction process is **copper metal (Cu)** and sulfur dioxide gas (SO2).

### Conclusion:
- Therefore, the metal copper is finally obtained by the reduction of cuprous oxide (Cu2O) with **cuprous sulfide (Cu2S)**.

### Answer:
The metal is finally obtained by the reduction of cuprous oxide with **cuprous sulfide (Cu2S)**.

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