Home
Class 12
PHYSICS
In the figure shown, the wedge is fixeda...

In the figure shown, the wedge is fixedand the masses are released from rest. The coefficient of friction between A and the incline is `mu_(1)` and B and the incline is `mu_(2)`. Then which of the following sentence is (are) correct
(I) normal reaction between A and B can never be zero
(II) normal reaction between A and B is zero only if `mu_(1) = mu_(2)`

A

I only

B

II only

C

both I and II

D

none

Text Solution

Verified by Experts

The correct Answer is:
D

if `mu_(1) lt mu_(2)`, then also `N gt 0`
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass m sides down an inclined right angled trough .If the coefficient of friction between block and the trough is mu_(k) acceleration of the block down the plane is

If the coefficient of friction between M and the inclined surfaces is mu = 1//sqrt(3) find the minimum mass m of the rod so that the of mass M = 10 kg remain stationary on the inclined plane

In which of the following cases the friction force between A and B is maximum in all cases mu_1=0.5 , mu_2=0 .

Coefficient of friction between A and B is mu . The minimum force F with which A will be pushed such that B will not slip down is -

If the coefficient of friction between A and B is mu , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

If the coefficient of friction between A and B is mu , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

The coefficient of friction between the block A of mass m and the triangular wedge B of mass M is mu . There in no friction between the wedge and the plane if the system (block A+ wedge B) is released so that there is no stiding between A and B find the inclination theta

A block of mass m is placed at rest on an inclination theta to the horizontal. If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is

Two blocks M and m are arranged as shown in the diagram The coefficient of friction between the block is mu_(1) = 0.25 and between the ground and M is mu_(2) = (1)/(3) If M = 8 kg then find the value of m so that the system will remain at rest