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Magnetic field B in a cylindrical region...

Magnetic field B in a cylindrical region of radius r varies according to the law `B = B_(0)t` as shown in the figure. A fixed conducting loop ABCDA of resistance R is lying in the region as show . The current flowing through the loop is

A

`(pia^(2)B_(0))/(12R)`

B

`(pi(r^(2)-a^(2))B_(0))/(12R)`

C

`(pi(b^(2) - a^(2))B_(0))/(12R)`

D

none of the above

Text Solution

Verified by Experts

The correct Answer is:
B
`e=(dphi)/(dt)=((r^(2)-a^(2)))/(2)(pi)/(6)(dB)/(dt)`
`:. i = ((r^(2)-a^(2))piB_(0))/(12R)`
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