The following electronic transition occurs when lithium atoms are sprayed into a hot flame,
`2s overset(I)rarr 2p overset(II)rarr 3d overset(III)rarr 3p overset(IV)rarr 4s overset(V)rarr 3p`.
Which of the transition would result in the emission of light?

Options

A. I, II and IV
B. III and V
C. III, IV and V
D. All of these steps

Explanation

To determine which electronic transitions in lithium atoms result in the emission of light, we need to analyze the transitions based on energy levels. The transitions are as follows:

1. **Transition I**: 2s → 2p
2. **Transition II**: 2p → 3d
3. **Transition III**: 3d → 3p
4. **Transition IV**: 3p → 4s
5. **Transition V**: 4s → 3p

### Step-by-Step Solution:

**Step 1: Identify the nature of transitions.**
- Emission of light occurs when an electron transitions from a higher energy level to a lower energy level.

**Step 2: Analyze each transition.**
- **Transition I (2s → 2p)**: This is from a lower energy level (2s) to a higher energy level (2p). **No emission occurs.**
- **Transition II (2p → 3d)**: This is also from a lower energy level (2p) to a higher energy level (3d). **No emission occurs.**
- **Transition III (3d → 3p)**: This is from a higher energy level (3d) to a lower energy level (3p). **Emission occurs.**
- **Transition IV (3p → 4s)**: This is from a lower energy level (3p) to a higher energy level (4s). **No emission occurs.**
- **Transition V (4s → 3p)**: This is from a higher energy level (4s) to a lower energy level (3p). **Emission occurs.**

**Step 3: Conclusion.**
- The transitions that result in the emission of light are **Transition III (3d → 3p)** and **Transition V (4s → 3p)**.

### Final Answer:
The transitions that result in the emission of light are **Transition III and Transition V**.