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The drawing shows a frictionless incline...

The drawing shows a frictionless incline and pulley. The two blocks are connected by a wire (mass per unit length, `mu = 25 g//m` ) and remain stationary. A transcerse wave on the wire has a speed of `60 m//s` relative to it. Neglect the weight of the wire relative to the tension in the wire. If the mass `m_(2)` be increased by `1%`, the speed of the transverse wave will be

A

`60.2 m//s`

B

`60.3 m//s`

C

`60.4 m//s`

D

`60.6 m//s`

Text Solution

Verified by Experts

The correct Answer is:
A
Tension, `T = (3m_(1)m_(2))/(2 (m_(1) + m_(2)))g , v = sqrt((T)/(mu)) , (delta v)/(v) = (1)/(2) (delta T)/(T) = (1)/(3) (delta m_(2))/(m_(2))` (where, `m_(1) ~~ 2m_(2)` )
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