A reaction is carried out at `600 K`. If the same reaction is carried out in the presence of catalyst at the same rate and same frequency factor, the temperature required is `500 K`. What is the activation energy of the reaction, if the catalyst lowers the activation energy barrier by `20 KJ//mol` ?

Options

A. 100
B. 120
C. 80
D. None of these

Answer

B

Explanation

`k = Ae^(- Ea//R xx 600)`
`k^(c ) = Ae^((Ea - 20)/(R - 500))`
`k = k^(c )`
`(Ea)/(R xx 600) = ((Ea - 20))/(R xx 500)`
`(Ea)/(6) = (Ea - 20)/(5)`
`20 = Ea - (5)/(6)Ea`
`Ea = 20 xx 6`
`Ea = 120 KJ//mol`