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The enthalpy of neutralization of a stro...

The enthalpy of neutralization of a strong acid with a strong base is -57.32 kJ/mole. The enthalpy of formation of water is -285.84 kJ/mole. The enthalpy of formation of hydroxyl ions is

A

`+ 228.52 KJ//mol`

B

`- 114.26 KJ//mol`

C

`- 228.52 KJ//mol`

D

`+ 114.2 KJ//mol`

Text Solution

Verified by Experts

The correct Answer is:
C
`H^(+) (aq). + OH^(-) (aq) rarr H_(2)O (l)`
`Delta_(r )H = Delta_(f)H_(H_(2)O) - (Delta_(f)H_((H^(+)(aq))) + Delta_(f)H_((OH^(-))))`
`-57.32 = 285.84 - (0 + Delta_(f)H_((OH^(-)(aq))))`
`Delta_(f)H_(OH^(-)(aq)) = -228.52 KJ//mol`
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