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The speed of the electron in the hydroge...

The speed of the electron in the hydrogen atom is approximately `2.2 xx 10^(6) m//s`. What is the centripetal force acting on the electron ifthe radius of the circular orbit is `0.53 xx 10^(-10) m`?Mass of the electron is `9.1 xx 10^(-31) kg`

A

`- 13.61 eV`

B

`- 6.8 eV`

C

`- 27.22 eV`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
`KE = (1)/(2)m xx v^(2) = (1)/(2) xx 9 xx 10^(-31) xx (2.2 xx 10^(6))^(2)`
`KE = (1)/(2) xx (9 xx 10^(-31) xx (2.2 xx 10^(6))^(2))/(1.6 xx 10^(-19))`
`KE = 13.61 eV`
`PE = -2 xx KE = -2 xx 13.61 = -27.22 eV`
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