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An aqueous solution has a density of 1. ...

An aqueous solution has a density of `1. 37 g//ml`. If molecular wt of solute is `68.5 g//mol`, then calculate molarity of solution.

A

`2 M`

B

`50 M`

C

`5 M`

D

`20 M`

Text Solution

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The correct Answer is:
To calculate the molarity of the solution, we can follow these steps: ### Step 1: Understand the formula for molarity Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] ### Step 2: Find the density and convert it to mass We are given the density of the solution as \(1.37 \, \text{g/mL}\). To find the mass of 1 liter of solution: \[ \text{Mass} = \text{Density} \times \text{Volume} \] Since 1 liter = 1000 mL: \[ \text{Mass} = 1.37 \, \text{g/mL} \times 1000 \, \text{mL} = 1370 \, \text{g} \] ### Step 3: Calculate the number of moles of solute We know the molecular weight of the solute is \(68.5 \, \text{g/mol}\). To find the number of moles: \[ \text{Moles} = \frac{\text{Mass}}{\text{Molecular Weight}} \] Substituting the values: \[ \text{Moles} = \frac{1370 \, \text{g}}{68.5 \, \text{g/mol}} \] ### Step 4: Perform the calculation for moles Calculating the above gives: \[ \text{Moles} = 20 \, \text{mol} \] ### Step 5: Calculate the molarity Now, we can substitute the number of moles and the volume of the solution into the molarity formula: \[ \text{Molarity} = \frac{20 \, \text{mol}}{1 \, \text{L}} = 20 \, \text{M} \] ### Final Answer The molarity of the solution is \(20 \, \text{M}\). ---

To calculate the molarity of the solution, we can follow these steps: ### Step 1: Understand the formula for molarity Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] ### Step 2: Find the density and convert it to mass We are given the density of the solution as \(1.37 \, \text{g/mL}\). To find the mass of 1 liter of solution: ...
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