`H_(2)C=CH-CH_(2)-overset(O)overset(||)C-H overset("Reagent")rarr`
`CH_(2)-CH_(2)-CH_(2)-CH_(2)-OH`
Appropriate reagent for above conversion will be

Options

A. Metal `+ H_(2)`
B. `LiAlH_(4)`
C. `NaBH_(4)`
D. None of these

Explanation

To solve the given question, we need to identify the appropriate reagent for the conversion of the compound with a double bond and an aldehyde group to the desired alcohol product. Here’s a step-by-step breakdown of the solution:

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- The reactant is an alkene with a terminal aldehyde: H₂C=CH-CH₂-CHO.
- The product is a straight-chain alcohol: CH₂-CH₂-CH₂-CH₂-OH.

2. **Understand the Reaction Type:**
- The reaction involves the reduction of an aldehyde (CHO) to an alcohol (OH) and the alkene (C=C) to a saturated alkane (C-C).

3. **Select the Reagents:**
- For the reduction of aldehydes and alkenes, we can use:
- Metal + H₂ (e.g., hydrogenation using a catalyst like Pd, Pt, or Ni)
- Lithium Aluminium Hydride (LiAlH₄)
- Sodium Borohydride (NaBH₄)

4. **Analyze the Effects of Each Reagent:**
- **Metal + H₂:** This reagent will reduce both the double bond (alkene) and the aldehyde group, converting the entire structure to a saturated alcohol.
- **Lithium Aluminium Hydride (LiAlH₄):** This reagent selectively reduces the aldehyde to an alcohol without affecting the double bond.
- **Sodium Borohydride (NaBH₄):** Similar to LiAlH₄, it will reduce the aldehyde to an alcohol but will not reduce the alkene.

5. **Determine the Final Product:**
- The desired product is CH₂-CH₂-CH₂-CH₂-OH, which indicates that both the double bond and the aldehyde need to be reduced.
- Therefore, the most suitable reagent for this conversion is **Metal + H₂**, as it will reduce both functional groups.

### Final Answer:
The appropriate reagent for the conversion is **Metal + H₂**.

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