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In solid phase, XeF(6) consists of...

In solid phase, `XeF_(6)` consists of

A

`XeF_(5)^(+) + F^(-)`

B

`XeF_(4) + F_(2)`

C

`XeF_(5)^(+) + XeF_(2)^(-)`

D

`XeF_(2) + 2F_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the solid phase of `XeF_(6)`, we will break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Structure of `XeF_(6)`**: - `XeF_(6)` consists of one xenon atom (Xe) and six fluorine atoms (F). - In the solid phase, the structure of `XeF_(6)` is often described as a distorted octahedral geometry. This means that the arrangement of the atoms is not perfectly symmetrical due to the presence of a lone pair of electrons on the xenon atom. **Hint**: Remember that the geometry can be influenced by lone pairs, which can cause distortion in the ideal shapes. 2. **Identifying the Lone Pair**: - In `XeF_(6)`, xenon has a total of 8 valence electrons. When it forms bonds with 6 fluorine atoms, it uses 6 of these electrons to form 6 bonds. This leaves 2 electrons, which form a lone pair. - The presence of this lone pair means that one of the positions in the octahedral structure is occupied by the lone pair instead of a fluorine atom. **Hint**: Consider how lone pairs affect molecular geometry and the overall shape of the molecule. 3. **Solid Phase Representation**: - In the solid phase, `XeF_(6)` can be represented as a combination of cations and anions. Specifically, it can dissociate into `XeF_(5)^(+)` (a cation) and `F^(-)` (an anion). - This means that in the solid state, `XeF_(6)` can be thought of as existing in the form of ionic species. **Hint**: Think about how ionic compounds are formed and how they can be represented in terms of cations and anions. 4. **Conclusion**: - Therefore, in the solid phase, `XeF_(6)` consists of `XeF_(5)^(+)` and `F^(-)`. This indicates that the solid structure is made up of these ionic components. **Hint**: Always check if the compound can be broken down into simpler ionic forms, especially for compounds involving noble gases and halogens. ### Final Answer: In solid phase, `XeF_(6)` consists of `XeF_(5)^(+)` and `F^(-)`.

To solve the question regarding the solid phase of `XeF_(6)`, we will break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Structure of `XeF_(6)`**: - `XeF_(6)` consists of one xenon atom (Xe) and six fluorine atoms (F). - In the solid phase, the structure of `XeF_(6)` is often described as a distorted octahedral geometry. This means that the arrangement of the atoms is not perfectly symmetrical due to the presence of a lone pair of electrons on the xenon atom. ...
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