Home
Class 12
PHYSICS
A block of mass 2kg is kept on a truck m...

A block of mass `2kg` is kept on a truck moving with a constant acceleration. The height 'h' of the block is `60 cm` and its width 'w' is `15 cm`. The surface between the block and the truck is sufficiently rough toprevent slipping. The minimum acceleration of the truck at which the topple is (take `g = 10 m//s^(2)` )

A

`2.5 m//s^(2)`

B

`3.5 m//s^(2)`

C

`4.5 m//s^(2)`

D

`5.5 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
For toppling of the block
`ma(h)/(2) gt mg(w)/(2)`
`a gt (w)/(h)g`
`a gt (15)/(60) xx 10`
`a gt 2.5 m//s^(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass 1 kg is placed on a truck which accelerates with acceleration 5ms^(-2) . The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A block of mass 2 kg rests on the floor of an elevator , which is moving down with an acceleration 'g' , then the apparent weight of the block is [ take g = 10 m//s^(2) ]

A 100 kg block is kept in the back of a truck moving with an acceleration of 2ms^(-2) There is no relative motion. What is the work done by frictional force on the block as truck is displaced by 2 m w.r.t. Ground

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a=5m//s^(2) Let N be the normal reaction between block and the wedge .Then (g=10m//s^(2) )

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

The elevator shown in figure is descending with an acceleration of 2m/s^2 . The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?

In figure calculate the linear acceleration of the blocks. Mass of block B= 8kg mass of disc shaped pulley =2kg (take g=10m//s^(2) )

A block of mass 5 kg is placed on a rough horizontal plane . The coefficients of stastic and kinetic friction between the block and surface are 0*5 and 0*3 respectively. A force of 100 N is applied at an angle 30^(@) with the horizontal as shown in the figure . The acceleration of the block will be [ g = 10 m//s^(2) ]