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The major product formed by the reaction...

The major product formed by the reaction of a anisole with
tert-butyl alcohol in presence of `Li//Liq NH_(3)` is

A

`1 -` methoxy cyclohexa `- 1, 4 -`diene

B

`2 -` methoxy cyclohexa `- 1, 3 -`diene

C

`1 -` methoxy cyclohexa `- 1, 3 -`diene

D

`3 -` methoxy cyclohexa `- 1, 4 -`diene

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the major product formed by the reaction of anisole with tert-butyl alcohol in the presence of lithium and liquid ammonia, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants are anisole (C6H5OCH3) and tert-butyl alcohol ((CH3)3COH). - Anisole has a methoxy group (-OCH3) attached to a benzene ring. 2. **Understand the Reaction Conditions**: - The presence of lithium and liquid ammonia indicates a reduction reaction. Lithium in liquid ammonia is a strong reducing agent. 3. **Reduction of Anisole**: - When anisole is treated with lithium in liquid ammonia, the methoxy group can be reduced. This leads to the formation of a cyclohexadiene structure. - The reaction involves the addition of hydrogen atoms to the aromatic ring, resulting in the formation of a double bond. 4. **Formation of the Intermediate Product**: - The reduction of anisole leads to the formation of cyclohexadiene with a methoxy group still attached. The structure can be represented as: - Cyclohexene with a methoxy substituent. 5. **Reaction with tert-Butyl Alcohol**: - In the presence of tert-butyl alcohol, the cyclohexadiene can undergo further reactions. The tert-butyl group can act as a leaving group, leading to the formation of a more stable product. - The reaction will involve the removal of two hydrogen atoms and the introduction of the tert-butyl group. 6. **Final Product Formation**: - The final product will be a substituted cyclohexene with a tert-butyl group and a methoxy group. The correct structure is cyclohexa-1,4-diene with a methoxy group. - The product can be named as 1,4-dimethoxycyclohexene. 7. **Conclusion**: - The major product formed from the reaction of anisole with tert-butyl alcohol in the presence of lithium and liquid ammonia is **cyclohexa-1,4-diene** with a methoxy group.

To solve the problem of determining the major product formed by the reaction of anisole with tert-butyl alcohol in the presence of lithium and liquid ammonia, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants are anisole (C6H5OCH3) and tert-butyl alcohol ((CH3)3COH). - Anisole has a methoxy group (-OCH3) attached to a benzene ring. ...
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