With Fe^(3+) ions [Fe(CN)(6)]^(4-) gives...

With `Fe^(3+) `ions `[Fe(CN)_(6)]^(4-)` gives prussian blue colouration due to the formation of ferri- ferro cyanide `Fe[Fe(CN)_(6)]_(2)` while with `NH_(4)SCN,Fe^(3+)` ion gives……. Colouration

A

`KMnO_(4)`

B

`K_(4)[Fe(CN)_(6)]`

C

`Fe_(4)[Fe(CN)_(6)]_(3)`

D

`[Fe(OH)_(3)]`

Verified by Experts

The correct Answer is:

C

`4Fe^(3+) + K_(4)[Fe (CN)_(6)] rarr Fe_(4) [Fe (CN)_(6)]_(3) + 4K^(+)`

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