Find out no of correct statements
(A) `N_(2)gtN` (Ist ionization Energy)
(B) `O_(2)gtO` (Ist Ionization Energy)
(C) `H_(2)gtH` (Ist ionization Energy)
(D) `N_(2)^(+)gtN_(2)^(-)` (Stability)
(E) `O_(2)gtO` (Ist Electron affinity)
(G) `Na_(2)CO_(3)gtLi_(2)CO_(3)` (Thermal stability)
(H) NO of co-ordinate bond in `P_(4)O_(10)` is `4`
(I) No of `pi` bond in `P_(4)O_(8)` is 2

Explanation

To determine the number of correct statements from the provided options, we will analyze each statement one by one.

### Step-by-Step Solution:

1. **Statement (A): `N_(2) > N` (1st Ionization Energy)**
- The last electron in `N2` is in a bonding molecular orbital, while in `N` it is in a pure p orbital. Bonding molecular orbitals are more stable than pure p orbitals.
- **Conclusion**: This statement is **correct**.

2. **Statement (B): `O_(2) > O` (1st Ionization Energy)**
- The last electron in `O2` is in an anti-bonding molecular orbital, while in `O` it is in a pure p orbital. Anti-bonding orbitals are less stable than pure p orbitals.
- **Conclusion**: This statement is **incorrect**.

3. **Statement (C): `H_(2) > H` (1st Ionization Energy)**
- Both electrons in `H2` are in bonding molecular orbitals, while in `H`, the electron is in a pure s orbital. Bonding orbitals are more stable than pure s orbitals.
- **Conclusion**: This statement is **correct**.

4. **Statement (D): `N_(2)^(+) > N_(2)^(-)` (Stability)**
- `N2^+` and `N2^-` have the same bond order, but the last electron in `N2^+` is in a bonding molecular orbital, while in `N2^-` it is in an anti-bonding molecular orbital. Therefore, `N2^+` is more stable.
- **Conclusion**: This statement is **correct**.

5. **Statement (E): `O_(2) > O` (1st Electron Affinity)**
- `O2` has a complete octet, while `O` does not. Therefore, the electron affinity of `O2` is less than that of `O`.
- **Conclusion**: This statement is **incorrect**.

6. **Statement (G): `Na_(2)CO_(3) > Li_(2)CO_(3)` (Thermal Stability)**
- As we move down the group in the periodic table, the metallic character increases, which in turn increases the thermal stability of the compounds.
- **Conclusion**: This statement is **correct**.

7. **Statement (H): Number of coordinate bonds in `P_(4)O_(10)` is `4`**
- The structure of `P4O10` shows that there are indeed 4 coordinate bonds.
- **Conclusion**: This statement is **correct**.

8. **Statement (I): Number of `pi` bonds in `P_(4)O_(8)` is `2`**
- The structure of `P4O8` shows that there are 2 pi bonds.
- **Conclusion**: This statement is **correct**.

### Summary of Correct Statements:
- Correct Statements: A, C, D, G, H, I
- Incorrect Statements: B, E

### Total Number of Correct Statements:
- There are **6 correct statements**.