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C(1) and C(2) are the two concentric cir...

`C_(1)` and `C_(2)` are the two concentric circles with radii `r_(1)` and `r_(2)(r_(1)ltr_(2))`. If the tangents drawn from any point of `C_(2)` to `C_(2)` meet again `C_(2)` at the ends of its diameter, then

A

`x^(2)+y^(2)=2`

B

`x^(2)+y^(2)=4`

C

`x^(2)+y^(2)=64`

D

`x^(2)+y^(2)=36`

Text Solution

Verified by Experts

The correct Answer is:
B, C
`tantheta=((-5+b)/(a+r)-(-5+b)/(a-r))/(1-((b+5)^(2))/(a^(2)-r^(2)))`
Now, `a^(2)=(r+4)^(2)-5^(2)`
`=r^(2)-9+8r`
`(b-5)^(2)=9`
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