Home
Class 12
CHEMISTRY
Which of the following compound have lar...

Which of the following compound have larger `C-O` bond length than `C-O` bond length of `H_(3)-overset(O)overset(||)(C)-CH_(3)`?

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds has a larger C-O bond length than the C-O bond length in acetone (H₃C-C(=O)-CH₃), we need to analyze the polarization and resonance effects in each compound. Here’s a step-by-step solution: ### Step 1: Understand the C-O Bond in Acetone - Acetone has a carbonyl group (C=O) where the carbon is bonded to two methyl groups (−CH₃). - The C=O bond in acetone is a double bond, which typically has a shorter bond length compared to a single bond (C-O). ### Step 2: Identify Factors Affecting Bond Length - The C-O bond length can increase if there is a polarization that leads to a partial positive charge on carbon and a partial negative charge on oxygen. - Resonance stabilization can also affect the bond length. If resonance allows for the delocalization of charges, it may lead to a longer bond length. ### Step 3: Analyze Each Option 1. **Option A**: Analyze the structure and polarization. - If polarization occurs, it creates a negative charge on oxygen and a positive charge on carbon. The presence of conjugation and following Huckel's rule (4n + 2 pi electrons) stabilizes the structure, potentially leading to a longer C-O bond length than in acetone. 2. **Option B**: Analyze the structure and polarization. - Similar polarization occurs, but this compound does not follow Huckel's rule (it has 4 pi electrons). Anti-aromatic compounds are less stable and do not favor polarization, leading to a shorter C-O bond length. Thus, this option can be eliminated. 3. **Option C**: Analyze the structure and polarization. - Polarization leads to resonance stabilization. The resonance structures allow for the delocalization of charges, which can result in a longer C-O bond length compared to acetone. 4. **Option D**: Analyze the structure and polarization. - This compound also shows polarization, but it has fewer alpha-hydrogens compared to acetone, making it less stable. Therefore, it is less likely to favor polarization, leading to a shorter C-O bond length than acetone. This option can be eliminated. ### Step 4: Conclusion - The compounds that have a larger C-O bond length than acetone are **Option A** and **Option C** based on their ability to stabilize polarization and resonance. ### Final Answer: **Option A and Option C have larger C-O bond lengths than acetone.** ---

To determine which of the given compounds has a larger C-O bond length than the C-O bond length in acetone (H₃C-C(=O)-CH₃), we need to analyze the polarization and resonance effects in each compound. Here’s a step-by-step solution: ### Step 1: Understand the C-O Bond in Acetone - Acetone has a carbonyl group (C=O) where the carbon is bonded to two methyl groups (−CH₃). - The C=O bond in acetone is a double bond, which typically has a shorter bond length compared to a single bond (C-O). ### Step 2: Identify Factors Affecting Bond Length - The C-O bond length can increase if there is a polarization that leads to a partial positive charge on carbon and a partial negative charge on oxygen. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Which of the following will have C=O bond length almost similar to C-O bond length?

Give the IUPAC name of the following compounds whose structures are given below : CH_(3)-CH_(2)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3)

Write the IUPAC name of the following compound : H_(3)C-overset(Cl)overset(|)(CH)-CH_(2)-overset(O)overset(||)(C)-CH_(3)

Which of the following can give iodoform test? (I) CH_(3)-overset(O)overset(||)C-CH_(2)-overset(O)overset(||)C-CH_(3) (II) C_(6)H_(5)-CH_(2)-overset(O)overset(||)C-CH_(3) (III) CH_(3)-CHO (IV) C_(6)H_(5)-overset(O)overset(||)C-CH_(3)

Give IUPAC name of the organic compound : (CH_(3))_(2)C=CH-overset(O)overset(||)(C)-CH_(3) .

Write the IUPAC name of the following compound: H_(3)C-overset(O)overset(||)(C)-CH_(2)-overset(Cl)overset(|)(CH)-CH_(3)

The order of stability of the following tautomeric compounds is (i). CH_(2)=overset(OH)overset(|)(CH)-CH_(2)-overset(O)overset(||)(C)-CH_(3)hArr (ii). CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3)hArr (iii). CH_(3)-overset(OH)overset(|)(C)=CH-overset(O)overset(||)(C)-CH_(3)