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The equation z^2 - (3 + i) z + (m + 2i) ...

The equation `z^2 - (3 + i) z + (m + 2i) = 0 m in R` , has exactly one real and one non real complex root, then product of real root and imaginary part of non-real complex root is:

A

Modulus of the non-real complex root is 2

B

the value of `m` is 3

C

Additive inverse of non-real root is `(-1-i)`

D

Product of real root and imaginary part of non -real complex root is 2

Text Solution

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The correct Answer is:
C, D

cd
If `alpha` is real root then `alpha=2, m=+-2`, non real root `=1+i`
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