Consider a parabola x^2-4xy+4y^2-32x+4y+...

Consider a parabola `x^2-4xy+4y^2-32x+4y+16=0`.
The focus of the parabola (P) is

A

`(2,1)`

B

`(-2,1)`

C

`(-2,1)`

D

`(2,-1)`

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The correct Answer is:

D

d
`(x-2y-4)^(2)=12(2x+y)`

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