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Figure shows the initial position of a s...

Figure shows the initial position of a system of two particles. Given that centre of mass of the system remains at rest particle `A` moves i a trajectory givenn by `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`
Pick the correct option (s) for the nature of `B's` trajectory and the coordinates of `B` at the instant when `A` was at the position `(0,b)`.

A

Trajectory of `B` is elliptical

B

Trajectory of `B` is circular

C

`(0,(-b)/2)`

D

`(a/2,(-b)/2)`

Text Solution

Verified by Experts

The correct Answer is:
A, D
`(2mx_(B)+mx_(A))/(3m)=a/3impliesx_(A)=a-2x_(B)`
`(2my_(B)+my_(A))/(3m)=0impliesy_(A)=2y_(B)`
Trajectory of `B` is `((a-2x)^(2))/(a^(2))+((2y)^(2))/(b^(2))=1`
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