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A solution containing 28 g phosphorous i...

A solution containing 28 g phosphorous in 315 g `CS_(2)` (b.p. = `46^(@)C`) boils at `47.9^(@)C and (K_(b) "for" `CS_(2) "is" `2.34^(@)C//"molar")`. What will be molecular formula of phosphorus ? (assuming complete association)

Text Solution

Verified by Experts

The correct Answer is:
4
`/_\T=(1000xxK_(b)^(')xxw)/(mxxW)`
`m_("exp")=123.8`
`(m_(N))/(m_("exp"))=1-alpha+(alpha)/n`
`:' alpha=1implies(m_(N))/(m_("exp"))=(alpha)/n`
`31/123.8=1/nimpliesn~~4`
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