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For any two vectors vecp and vecq, show ...

For any two vectors `vecp` and `vecq`, show that `|vecp.vecp le|vecp||vecq|`.

A

`lamda_(1)=(alpha)/(vecp.vecq)`

B

`lamda_(2)=1/(vecp.vecq)`

C

`lamda_(2)=1/(vecr.vecq)`

D

`lamda_(1)=(alpha)/(vecr.vecq)`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`vecpxx(vecx xx vecq)=(vecp.vecq)-(vecp.vecx)vecq=vecpxxvecr`
`vecx=((vecp.vecx)vecq)/(vecp.vecq)+((vecpxxvecr))/(vecp.vecq)=(alpha)/(vecp.vecq) vecq+((vecp+vecr))/(vecp.vecq)`
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