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Four horses compete in a race. Let N be ...

Four horses compete in a race. Let N be the total number of different orders in which the horses can cross the finish line. Assume that all four horses finish the race and two or more horses can cross the finishing line together. The value of `N/(10)` is (where [.] denotes greatest integer function)

A

`[(alpha)/6]=12`

B

`[(alpha+1)/10]=7`

C

`[100/(alpha)]=2`

D

`(alpha)/12=beta, beta epsilon I`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`1+.^(4)C_(1)xx2+(|__4)/(|__2|__2|__2)xx|__2+(|__4xx|__3)/(|__2|__1|__1|__2)+|__4=75`
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