One mole of `SO_(2)Cl_(2)` on hydrolysis gives acids which can be neutralized by `x` moles of `NaOH`. The value of `x` is?

Explanation

To solve the problem, we need to determine how many moles of NaOH are required to neutralize the acids produced from the hydrolysis of 1 mole of \( SO_2Cl_2 \).

### Step-by-Step Solution:

1. **Identify the Hydrolysis Reaction**:
The hydrolysis of \( SO_2Cl_2 \) (sulfur dichloride) in the presence of water can be represented as:
\[ SO_2Cl_2 + H_2O \rightarrow H_2SO_4 + 2HCl \]
This reaction shows that one mole of \( SO_2Cl_2 \) produces one mole of sulfuric acid (\( H_2SO_4 \)) and two moles of hydrochloric acid (\( HCl \)).

2. **Determine the Total Number of Acidic Hydrogens**:
- \( H_2SO_4 \) has 2 acidic hydrogens.
- \( HCl \) has 1 acidic hydrogen, and since there are 2 moles of \( HCl \), this contributes 2 acidic hydrogens as well.
- Therefore, the total number of acidic hydrogens from the products is:
\[ 2 \, (from \, H_2SO_4) + 2 \, (from \, 2HCl) = 4 \, acidic \, hydrogens \]

3. **Neutralization with NaOH**:
Each mole of \( NaOH \) provides one hydroxide ion (\( OH^- \)), which can neutralize one acidic hydrogen (\( H^+ \)). Since we have 4 acidic hydrogens, we will need 4 moles of \( NaOH \) to neutralize them:
\[ 4 \, H^+ \, \text{(from acids)} \rightarrow 4 \, OH^- \, \text{(from NaOH)} \]

4. **Conclusion**:
Thus, the value of \( x \), which represents the number of moles of \( NaOH \) required to neutralize the acids produced from the hydrolysis of 1 mole of \( SO_2Cl_2 \), is:
\[ x = 4 \]

### Final Answer:
The value of \( x \) is 4.

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