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The mole fraction of solute in some solu...

The mole fraction of solute in some solution is `1//n`. If `50%` of the solute molecules dissociates into two parts and remaining `50%` get dimerized now mole fractions of solvent become `4/5`. Find value of `n`.

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To solve the problem step by step, let's break it down: ### Given: - Mole fraction of solute = \( \frac{1}{n} \) - 50% of solute dissociates into 2 parts. - 50% of solute dimerizes. - Mole fraction of solvent = \( \frac{4}{5} \) ### Step 1: Understand the dissociation and dimerization Let’s denote the initial number of solute molecules as \( x \). - After dissociation: - 50% of \( x \) dissociates into 2 parts, so the number of particles from dissociation = \( 0.5x \times 2 = x \). - After dimerization: - The remaining 50% of \( x \) dimerizes, which means \( 0.5x \) forms \( \frac{0.5x}{2} = 0.25x \) dimers (since each dimer consists of 2 molecules). ### Step 2: Calculate total number of solute particles Now, the total number of solute particles after these processes is: - From dissociation: \( x \) - From dimerization: \( 0.25x \) Total number of solute particles = \( x + 0.25x = 1.25x \). ### Step 3: Determine mole fraction of solute and solvent The mole fraction of the solvent is given as \( \frac{4}{5} \). Therefore, the mole fraction of the solute is: \[ 1 - \text{mole fraction of solvent} = 1 - \frac{4}{5} = \frac{1}{5} \] ### Step 4: Set up the equation for mole fraction We know that the mole fraction of solute is also given by: \[ \text{Mole fraction of solute} = \frac{\text{number of solute particles}}{\text{number of solute particles} + \text{number of solvent particles}} \] Let’s denote the number of solvent particles as \( y \). Thus, we have: \[ \frac{1.25x}{1.25x + y} = \frac{1}{5} \] ### Step 5: Solve for \( y \) Cross-multiplying gives: \[ 5 \times 1.25x = 1.25x + y \] \[ 6.25x = 1.25x + y \] \[ y = 6.25x - 1.25x = 5x \] ### Step 6: Substitute into the mole fraction of solute Now, substituting back into the mole fraction equation: \[ \frac{1}{n} = \frac{1.25x}{1.25x + 5x} \] \[ \frac{1}{n} = \frac{1.25x}{6.25x} \] \[ \frac{1}{n} = \frac{1.25}{6.25} \] \[ \frac{1}{n} = \frac{1}{5} \] ### Step 7: Solve for \( n \) From the equation above, we can see that: \[ n = 5 \] ### Conclusion Thus, the value of \( n \) is: \[ \boxed{6} \]

To solve the problem step by step, let's break it down: ### Given: - Mole fraction of solute = \( \frac{1}{n} \) - 50% of solute dissociates into 2 parts. - 50% of solute dimerizes. - Mole fraction of solvent = \( \frac{4}{5} \) ...
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